integrate e^x[e^2x - e^(2-x)] to the limit of 1 and 0
answer provided is -1.03...
i simplified the equation before integrating, so i got e^3x - e^2
want to know where i went wrong, thanks
Hi
Integrate e^3x - e^2 from 0 to 1
= [1/3 e^3x - (e^2)(x) ] from 0 to 1
= { 1/3 e^3 - e^2 } - {1/3 (1) - 0 }
= -1.03
My guess is you forgot to include that e^0 is 1
A lot of students are careless about this area.