Hello, I really need some help with some questions in my Partial Fractions homework..
6. x
----------------
(1-x^2)(x-1)
9. 2x^3
----------------------
(1+x^2)(1-x)^2
10. x^2 + 3x
---------------
x^2 - 4
11. x^3 - x^2 - 4
--------------------
x^2 - 1
I need to express these as partial fractions..
Whats the question?
Find x?
Har? How to find x when no opposite side????
he wana simplify them?
i did the easier questions.. must use the formula mah.. they just want me to express them as partial fractions.
pple... express it as partial fractions...
i.e. first question
Try the rest guys :D
Ohhh...that.
I'm getting too rusty.
huh? how did u suddenly get 1/4 and 1/2? sub what and what? i seem to be getting it wrong..
either, you split into A & B then multiply denominator, or you compare coefficient... or what's the other method huh.. forgot
ahh.. damn im so screwed.
hooray
2 weeks due hw for pewpew
Originally posted by pewpew:huh? how did u suddenly get 1/4 and 1/2? sub what and what? i seem to be getting it wrong..
hmm.... i skipped a few steps...
One fool proof way is to do
A/(1+x) + B/(1-x) + C/(1-x)^2
then solve the coefficients
Hi,
For Q10 & Q11, the rational expression is improper. You need to use long division or algebraic manipulation before finding partial fractions.
By algebraic manipulation, the numerator in Q10 may be written as (x^2 - 4) + 3x + 4.
In addition, note the following pointers:
1. Can the denominator be factorised? For example, x^2 - 1 = (x - 1)(x + 1).
2. Recall the three decomposition rules which can be found in the formulae booklet, which will accompany you for all tests and examinations:
(i) linear factors,
(ii) repeated linear factors,
(iii) quadratic non-factorisable factors (e.g. x^2 + 1).
3. Use of the cover-up method to find constants, or comparing coefficients of x, x^2, etc.
Thanks!
Cheers,
Wen Shih