Solve the equation 6x cube + 11 x square - 3 x - 2 = 0. Hence find the values of teta (the one with an 0 and cut into half) , between 0 degree and 180 degree, which satisfy the equation 6 tan square teta + 11 tan teta - 3 = 2 cot teta
this is basic trigo
6 tan^2 y + 11 tan y -3 = 2 cot y
6 tan^2 y + 11 tan y -3 = 2/(tan y)
6 tan^3 y + 11 tan^2 y -3tan y -2 =0
Hence the solutions for x are the solution for tan y.
Continue by applying basic trigo.