An object 3cm high is placed 12cm from a converging lens. A real image is found to form 36cm from the lens.
(a)what is the height of the image?
I never took physics but can I guess? 9cm?
4 cm
Originally posted by bonkysleuth:An object 3cm high is placed 12cm from a converging lens. A real image is found to form 36cm from the lens.
(a)what is the height of the image?
You can easily use E maths' similarity here
If you draw only the ray that passes through the optical centre of the lens, you will see similar triangles. We can ignore the other ray that cuts through the focal length, because the distances of the images from the lens are already given.
So using similarity, height of image / 36 = 3 / 12
height of image = 9 cm