Maths help Needed Part 3 x.x URGENT >.<
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If there any tips of approach upon doing number sequence i am currently struck with ...
Given:
The first five term of a sequence are 1,3,6,10,15
formula 1/2n(n+1)
Write down an expression in terms of n for the n^th term of the sequence
3,6,10,15,21
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any formula to memorise or something?
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How come like the first formula given is already wrong?
Oh i see it, it's (1/2) [n(n+1)]
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then the nth term should be (1/2)[n(n+1)] + n+1
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Visit here maybe http://emaths.sgforums.com/forums/3156/topics/334428
Ya it's (1/2)[(n+1)(n+2)]
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Hmm how do you guys go about dealing this question is there actually any formal appearing in ur head before u do them?
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This kind of thing is also a killer to me too.
deteq did it right.
(1/2) [n(n+1)] for 1,3,6,10,15
for 3,6,10,15,21 it's almost the same except the numbers have grown by 2,3,4,5,6
n1+a = 2
n2+a = 3 ...
a = 1
so (1/2) [n(n+1)]+n+1 is the answer. I merely expanded on his answer.
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gee nobody saw my thread?
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i saw, but I still don't know how you guys solve it. care to teach again :D
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hmmm
might be a bit too late... it's a pity my set of 25 number patterns questions was lent to a student few years ago, and was lost :(
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Originally posted by eagle:
hmmm
might be a bit too late... it's a pity my set of 25 number patterns questions was lent to a student few years ago, and was lost :(
ermmm....don't you make copies?
kids at those age aren't exactly responsible people.
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Originally posted by maurizio13:
ermmm....don't you make copies?
kids at those age aren't exactly responsible people.
that was when I just started tuition not long ago... :(
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Originally posted by eagle:
that was when I just started tuition not long ago... :(
i am sure you make copies now.
