A and B are 2 houses, 40 m apart, on the same horizontal line as the foot F of a building TF. The angles of depression of A and B from top of building are 25 deg and 58 deg respectively. Find the possible heights of the building.
answer's are 26.3m and 14.4 m. I can't get 14.4m...
Please do reply swiftly if possible because i'm having my exam tomorrow. thanks.
A and B can be one on each side of the building
or both on the same side
as in
A----- F---------B
or
F ----B-----A
(smaller angle of depression = further away)
u need to have 2 diagrams
Originally posted by FireIce:A and B can be one on each side of the building
or both on the same side
as in
A----- F---------B
or
F ----B-----A
(smaller angle of depression = further away)
u need to have 2 diagrams
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There are two different ways for the houses to be placed
Taking the difference of the ground distance,
h / tan 25° - h / tan 58° = 40
h (1 / tan 25° - 1 / tan 58°) = 40
1.5196 h = 40
h = 26.3 m
Taking the summation of the ground distance,
h / tan 25° + h / tan 58° = 40
h (1 / tan 25° + 1 / tan 58°) = 40
2.769 h = 40
h = 14.4 m
Answer placed on ExamWorld as well. Thanks for the contribution :D
Regards,
Eagle