E maths - bearings

• bonkysleuth

  22 Sep 08, 18:14

  A point B is 500 m due North of a point A. Rahmat walks from A on a bearing of 325 deg.

   

  Find Rahmat's distance from A when he is

  (i)due West of B.

  (ii) equidistant from A and B

  (iii) Closest to B

   

  Would help if a diagram is provided to facilitate explanation. However, without other teaching aid is fine with me too. THANK YOU!

• eagle

  22 Sep 08, 19:08

  (i) bearings of 325° = 35° anti-clockwise as shown:

  

  
  Hence, distance from A = 500 / cos 35°
  = 610.4 m
  
  
  (ii) Diagram is as shown:
  
  
  
  Distance from A = 250 / cos 35°
  = 305.2 m
  
  
  (iii) Diagram is as shown:
  
  
  
  Distance from A = 500 * cos 35°
  = 409.6 m

   

  Answer put on ExamWorld as well. Thanks.
  Do help to verify it by yourself too!

   

  Regards,
  Eagle
  ExamWorld
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