The curve C is defined parametrically by
x = (1+t)^(2/3),
y= ln (t^2), t<=-1
Show that the area of the region enclosed by C, the lines x=0, x=1 and the x-axis can be expressed in the form [definite integral from a to b] f(t) dt, where a and b are constants to be determined.
Hence evaluate this area.
Thanks in advance!
Thanks for the wonderful softwares and steps, but..
How to get a=-1 and b=-2?
Can you also draw the graph out?
find out what is y when x=0, what is y when x = 1
just draw a curvy line from (0, -1) to (1, -2)