Complicated questions D=
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ignore everything below, problems solved
we've chopped the questions and the first question above already.
the answer to the first one is 9.423 m/s^2
we're still having trouble with the 2nd
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the second question looks simple but it's not that simple. take note the thing is not at origin. we found r using Pythagoras, and theta dot. r dot cannot be zero. v = r x theta dot does not work because we cant assume r dot to be zero. we're given an equation, i was thinking differentiating that to find the gradient of velocity, and thus finding the angles using inverse tan, but what do we do with that?
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got final answer ma? maybe it'll be easier to do the working with that.
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hahah i wish we had an answer!
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can copy the questions out?
I can't see images at the moment.
These few days quite busy because getting more students...
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the questions are actually quite dependent on the image in a way. but dont worry man, just chopped the second question this morning! problem solved
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hie, can post ur solution?
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the working is a little -.- and hard to type out lol, but the correct answers are 1) 9.423 m/s^2 2) 16.593 m/s for the second one you have to: differentiate equation - (1) substitute y= 11 into the equation to get x substitute the x you found above into (1) - (2) tan theta = (2) it's all angle work, similar triangles and stuff in between here. eventually you take a small angle away from a big angle to get the angle with the velocity (the gradient at y = 11) cos (angle with velocity) = (r x theta dot) / v theta dot is your rev/min converted to rad/sec r is found by using trig