looks almost correct
but as x tends to infinity or - infinity, i seems that the gradient increases faster and faster... So your red curve shouldn't really be concave downwards at both ends I think...
Originally posted by limywv:thanks for the reply, but am I right by spltting the f graph into 4 parts, the most-left portion i see it as having a decreasing Positive gradient, so the f' graph for that part should be on the positive y plane
Ok so how about the next qn, i seriously not sure of it..
the left-most part is actually increasing positive gradient. Do look again. Decreasing means you should see it tending to a turning point again.
the next question, do it the same way as you have done lor.... when x is -ve infinity or infinity, f'(x) = 0
then as x tends to zero, your f'(x) will curve up, then curve down again to zero where f(x) is at the turning point, then curve up again, then down back to zero again... You f'(x) graph will look something like a camel double hump