need help with enigneering mechanics!
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if u know how do plssss help!!thankssss
http://img79.imageshack.us/my.php?image=65799954ji0.png
and
http://img141.imageshack.us/my.php?image=70722147sw3.png
thanksss
The Figure shows two forces applied to the light beam AB. If P = 175 N, determine the sum of moments of the forces at A in Nm. You may take clockwise as positive direction.
The Figure shows a light horizontal beam ABC that is loaded by the force P = 100 N. The beam is held in a state of equilibrium by the pin-joint at A and the light cable that passes through a smooth pulley at D. The cable is attached to the beam at locations B and C.(a) The tension in the cable is N;(b)Give your answers to the nearest one decimal place.(b) The magnitude of the reaction at A is N.
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At least copy out the question la...
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Originally posted by eagle:
At least copy out the question la...
hm?i dunno how to paste the question on my post.errrr..the question is all there liao -
means copy the words out...
select, copy paste...
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Originally posted by eagle:
means copy the words out...
select, copy paste...
but need see the picture then can do -
can copy that picture out also...
next time you do that hor... if not I change here change there read very troublesome
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Originally posted by eagle:
can copy that picture out also...
next time you do that hor... if not I change here change there read very troublesome
copy liao..but my laptop cannot see the pic=( -
first question for
http://img79.imageshack.us/my.php?image=65799954ji0.pngclockwise moments = 300 (value of P) x 1.2m = 360Nm
anticlockwise moments = ( 0.8Fb + 1.6Fc ) Nm, where Fc is T, Tension, Fb is upward force at point B
but Fb = T sin 40
Thus, (0.8sin 40 + 1.6) T Nm = 360 Nm
T = 170.3 N-- change the values accordingly when your question changed values... --
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for 2nd question
http://img141.imageshack.us/my.php?image=70722147sw3.pngclockwise moments = 200 * 0.8 Nm = 160 Nm
anti-clockwise moments = P sin 30 * 2m = 156 Nm
Result:
160 - 156 = 4Nm (since clockwise is positive)-- change the values accordingly when your question changed values... --
Btw, next time save it in jpg or gif or bmp form... This forum cannot display png graphics
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Originally posted by eagle:
for 2nd question
http://img141.imageshack.us/my.php?image=70722147sw3.pngclockwise moments = 200 * 0.8 Nm = 160 Nm
anti-clockwise moments = P sin 30 * 2m = 156 Nm
Result:
160 - 156 = 4Nm (since clockwise is positive)-- change the values accordingly when your question changed values... --
Btw, next time save it in jpg or gif or bmp form... This forum cannot display png graphics
orhh..hahaha thanks!but the first question u did is wrong lehh..i only get 4 points from the 2nd question u did..
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did u change the values, be it force or angle, accordingly?
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Originally posted by eagle:
did u change the values, be it force or angle, accordingly?
i didnt change cus the values were the same -
same as the picture, or same as the question in text format...
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Originally posted by eagle:
same as the picture, or same as the question in text format...
its exactly same as the picture..the values angle n everything same de -
The question 2 and question 1 u tell me till blur.... Which one is which one now?
2nd question I did is worth 4 points according to the picture what...
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Originally posted by eagle:
The question 2 and question 1 u tell me till blur.... Which one is which one now?
2nd question I did is worth 4 points according to the picture what...
sorry sorry..i meant this question is wrong
http://img79.imageshack.us/my.php?image=65799954ji0.png -
so part a is wrong is it?
cuz I just realised I forgot to do part b...
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Originally posted by eagle:
so part a is wrong is it?
cuz I just realised I forgot to do part b...
yep yep. anyway why the 0.8sin40 must plus 1.6 ar? -
Originally posted by IfUWantHateMe:
yep yep. anyway why the 0.8sin40 must plus 1.6 ar?hmm... was busy whole day.... I try work it out again tmr after my work.... Quite busy these few days... Many things to settle...
