circuits queston

• ChoCoChips

  2 May 08, 21:44

  

  pls help me.

  i do liao but dunno answer correct anot.

  thanks!

• ispyyy

  2 May 08, 22:13

  lol... try ah...

  Input Voltage

  = 240( sin 2*pi*50 + jcos 2*pi*50)

  = 240( -0.26 +j0.96)

  = -62.4 +j230.4

  Total input impedence

  = 1/(1/z1 + 1/z2 + 1/z3)

  =2.33+j1.1

  Total current

  = Total voltage/Total impedence

  = 16.27+j91.2

  Total input power

  =| Re {VI} |= 22028

  Total reactant power

  = | Img {VI} | = 1941

   

  jwC + 1/Zin = Re number

  Hence,

  if 1/Zin = 0.35-j0.17,

  jwC = j0.17

  C = 5.4x 10E-4 F

   

   

   

• ispyyy

  2 May 08, 22:16

  I forgot on the power fomular...

  Dont noe it is the real number of whole answer or real number x real number....

  hahaahaha...

  Check it out yrself lor...

  :p

   

• ChoCoChips

  2 May 08, 22:26

  die.

  i got different values leh.

  hahaha chui liao la me

• ispyyy

  2 May 08, 22:29

  Originally posted by ChoCoChips:

  die.

  i got different values leh.

  hahaha chui liao la me

   

  who noes???

  u maybe correct lor...

  I long long long long long time never do this type of question liao... :p

   

• ChoCoChips

  2 May 08, 22:30

  eh and hor,

  why input voltage ish got the cos and sin one?

  i tot it's just 240v and 0 degrees only?

• ispyyy

  2 May 08, 22:36

  Originally posted by ChoCoChips:

  eh and hor,

  why input voltage ish got the cos and sin one?

  i tot it's just 240v and 0 degrees only?

  oh ya hor... me mess up liao...

  hahahaaa... it is 240V with 0 degrees...

  :p