Draw te graph of y = 2x^2 +1 for =3 equal to or less than X, equal to or less than 3.
By drawing a tangent , find the gradient of the curve at the point
B (2,9)
The answer's 8 but i got 6.6....
Draw the graph of y = x^3 for -2< or equal to x < or equal 2
by drawing a tangent, find gradient of curve at the point where x = -1.
the answer's 3 . but i got 4 despite many tries. could someone try drawing this out and see whether the answer scheme is correct??
this kind of thing.. u have to see whether ur graph good or not one la..
ALTERNATIVELY..
qn1.
u noe how to do differentiation rite?
dy/dx = 4x.. sub x = 2 u get 8 lo.. haha..
qn 2.
dy/dx = 3x^2.. sub x = -1, u get 3 lo.. haha..
so i can tell u.. if u draw ur graph correctly, u shud get the answer.. so the only problem is ur graph drawing
Make sure your graph is smooth, and tangent only touches one point.