two quick maths problems

WoAiMeiMei

15 Apr 08, 18:06

-all questions completed-

eagle

15 Apr 08, 18:12

if not in rush, I do tmr night... I have my fyp ca4 presentation tmr morning

WoAiMeiMei

15 Apr 08, 18:13

wth does the second question mean? >_<

hmm due thurs at 6

weewee

15 Apr 08, 18:16

Originally posted by WoAiMeiMei:

will work on this tonight, just need comparisons because scared i'll stuff up hey : O

Q1) when x = 1.6

6y^2 +6y=8(1.6) +7=19.8

6y^2 +6y-19.8=0

y=[-6+-sqrt(36-4*6*-19.8)]/12

y=1.3841 or y=negative number (rejected)

At this point, differentiate implicitly with respect to x.

(12y + 6 )(dy/dx) = 8

dy/dx = 0.3538

weewee

15 Apr 08, 18:30

For Q2) I am not sure but w-axis is a 3dimensional axis but it is not like the z-axis. Since it is protrayed at an angle, it means w-axis is not completely independent from the x and y-axis. The angle 235 degree means it is an 360-235=125degree looking from the other direction. It means the w-axis make a 125 degree wrt to the x and y axis.

WoAiMeiMei

15 Apr 08, 18:36

haha i will check that out later after i complete a few sets. thanks for the help! be back soon!

eagle

15 Apr 08, 18:41

me going to vote weewee as moderator

WoAiMeiMei

15 Apr 08, 19:48

i think the question asks for the "w" component of the vector? :s not sure

WoAiMeiMei

15 Apr 08, 20:01

crap... what are gradient units for q1? it's not m

theoratically it shuld cancel out -__-

FirePig

15 Apr 08, 20:03

gradient is distance over distance. metres over metres. of cos cancel out lor.

WoAiMeiMei

15 Apr 08, 20:14

is it me or did weewee forget the 6 infront of the y^2?

@firepig: the program is hell effed up. u need to use "m/m" as ur units. wth

16/f/lonely

15 Apr 08, 20:15

Dont think qn 2 is asking for 3D graph component.