There's this TYS qn (D04/P1/Q15)
Water of depth 10 m exerts a pressure equal to atmospheric pressure. An air bubble rises to the surface of a lake which is 20 m deep. When the bubble reaches the surface, its volume is 6 cm3. What was the volume of the air bubble at the bottom of the lake?
A 2 cm3 (Ans) B 3 cm3 C 12 cm3 D 18 cm3
Can somebodi enlighten me (in detail) as to how to find the volume? Wat formula do I use?
Domo Arigato Gozimasu
i taught this to my ex tuition students before. 2 of them asked the same question.
at surface:
pressure, P1 = 1atm (atmospheric pressure equivalent to 10m of water), V1 = 6cm3
at bottom of lake:
pressure, P2 = 3 atm (atmospheric pressure + 20m of water), V2 = unknown
Using Bolye's Law, P1V1 = P2V2
V2 = 2cm3
Thanx 4 ur prompt reply. I understand liao!
Wahhhhhhs. If O'level pop this question out, I'll throw away marks for sure. :<. I don't understand at all.